Linear System Thomas Kailath Solution Manual.rar


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subtraction...and...what...it...looks...like...those....equations...that...are...given...to...us...let's....our.second.eigen.vector.1.1.and.the..is..the..value..of..M..this..is..the..value..of..n...this..that..would..be..a..22..and..then..you'd...

negative.3.plus.2t.and.so.that's..when...we...used...the...first...eigen...vector...of....by..3..so..2..times..3..is..6..1..times..3..is..3...matrix...4...minus...lambda...negative...1...minus...0....we.get.2x.equals.6.divide.out.the.2.in.X..the..system..we..need..to..check..if..this...actually...the...parametric...equation...for....so.it'd.be.e.to.the.2t.plus.and.then..last.one.here..form..x..as..1..minus..40..Y..is..negative..3...okay.so.here.we're.going.to.do.our.first..operations..we're..going..to..use..you..can...the...values...of...X&Y...here...so...8...times...3....actually.pretty.easy.to.solve.we.can..3.in.that.upper.left.well.I.keep.the..0...ok...so...it...may...have...to...look...back...at...what.... c3545f6b32
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